1.
fosfatul de potasiu = K3PO4
raport atomic
K: P: O = 3: 1: 4
raport de masa
avem 3x39g K , 1x31g P si 4x16g O
K: P: O = 117: 31: 64
2.
m.AlCl3 = 1x27+3x35,5 = 133,5 g/mol
130g m g
2Al + 3Cl2 --> 2AlCl3
2x27 2x133,5
=> n = 130x2x133,5/2x27 = 642,78g AlCl3
3.
M.CaO = 40+16 = 56 g/mol
n moli 12g
2Ca + O2 --> CaO
2 56
=> n = 2x12/56 = 0,43 moli Ca
4.
M.H2O = 2x1+16 = 18 g/mol
500 L m g
2H2 + O2 --> 2H2O
2x22,4 2x18
=> m = 500x2x18/2x22,4 = 401,8 g H2O
5.
M.FeCl3 = 56+3x35,5 = 162,5 g/mol
10x10la24 m g
2Fe + 3Cl2 --> 2FeCl3
3x6,022x10la23 2x162,5
=> m = 10x10la24x2x162,5/3x6,022x10la23
= 1800 g FeCl3 rotunjit