Explicație:
Răspuns:
p=m,px100/m,i---> m,p=500x80/100g= 400gMgCO3 PUR
miu,MgCO3=84g/mol
miuMgO=40g/moL
miu,Mg(OH)2=58g/mol
84g...................40g
MgCO3----> MgO + CO2
400g...............x
x=m=190,5gMgO
40g............................58g
MgO + H2O---> Mg(OH)2
190,5g......................x
x=m=276,2gMg(OH)2= md
c=mdx100/ms----> ms= 276,2x100/58g=476g sol.
vreau coroană daca se poate