Răspuns:
[tex]a=0,2-0,1(6)+0,5=\frac{2(2}{10} -\frac{15(15}{90} +\frac{5(5}{10} =\frac{1(6}{5} -\frac{1(5}{6} +\frac{1(15}{2} =\frac{6-5+15}{30} =\frac{16(2}{30} =\frac{8}{15}[/tex]
[tex]b=0,5+1,4*(\frac{2)2}{3} +\frac{1}{6} )=\frac{5}{10} +\frac{14}{10} *\frac{5}{6} =\frac{3)1}{2} +\frac{7}{6} =\frac{10(2}{6} =\frac{5}{3}[/tex]
[tex]c=(\frac{2}{3} +\frac{1}{6}):\frac{7}{3} *0,4=\frac{5}{6} *\frac{3}{7} *\frac{4}{10}=\frac{1}{7}[/tex]
(15, 3, 7)=105
[tex]a=\frac{7)8}{15} =\frac{56}{105}[/tex]
[tex]b=\frac{35)5}{3} =\frac{157}{105}[/tex]
[tex]c=\frac{15)1}{7}= \frac{15}{105}[/tex]
15<56<157 ⇒ c<a<b
Explicație pas cu pas:
