Răspuns:
[tex]( \frac{3)1}{2} + \frac{2)1}{3} + \frac{1}{6} ) {}^{2011} \div ( \frac{4}{12} {}^{2} = ( \frac{3}{6} + \frac{2}{6} + \frac{1}{6}) \div \frac{4}{12} {}^{2} = ( \frac{6}{6} ) {}^{2011} \div \frac{16}{144} = 1 \times \frac{144}{16} = 1 \times 9 = 9[/tex]
Succes.!
