Schlachterryan2011ask
a fost răspuns

308. Dacă: a = 20 + (100 - 8x8 - 4 x 2),
b = 50 - (65 - 3 x 6 + 1),
c = 2 + 27:9 + 21:7 - 2 x 1,
calculează:
a) a : (b + c)
b) 2 x a + 2 x b - 4xc;
c) 2 x a : (b + c) + a
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Răspuns :

Brybry10ask

a=20+(100-68-8)

a=20+(32-8)

a=20+24

a=44

b=50-(65-18+1)

b=50-(47+1)

b=50-48

b=2

c=2+3+3-2

c=7+3-2

c=10-2

c=8

Maya2009ask

Răspuns:

a=20+(100-8×8-4×2)

a=20+(100-64-8)

a= 20+28

a=48

b=50-(65-3×6+1)

b=50-(65-18+1)

b=50-48

b=2

c=2+27:9+21:3-2×1

c=2+3+7-2

c=5+7-2

c=10

a) a:(b+c)

48:(2+10)=

48:12=4

b)2×a+2×b-4×c=

2×48+2×2-4×10=

96+4-40=

100-40=60

c)2×a:(b+c)+a

2×48:(2+10)+48=

96:12+48=

8+48=56

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