Lia1998ask
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Afla formula oxizilor de azot, daca in primul oxid azotul constituie 30.43%, iar in al doilea 63.63%

Răspuns :

Sudoku95ask
%N=masa azot/masa molara oxid * 100
N2Ox => masa molara = 2*14+x*16=28+16x
masa molara oxid 1 = 28*100/30,43 = 92 =>28+16x=92=>16x=64=>x=4
N2O4=>NO2 - dioxidul de azot
masa molara oxid 2 = 28*100/63,63 = 44 =>28+16x=44=>16x=16=>x=1
=>N2O - protoxid de azot