6. Rezolvaţi prin metoda reducerii sistemele:
3x + 2 y =1 5x+4y=-4
a)
b)
(2x+3y=-2
4x + 3y = 3
C)
(3x + 5y = 8 (3x+4y=-1
S2x+y=-2 (2x- y=1
3x - 5y = 18
f)
4x + 5y = 8 (3x +2y=19
(6x+4y=-6
Sx+y=-1
d)
5x+2y=7
(2x+3y=14
h)
(4x - 5y=6
e)