Răspuns:
miu, C4H6=54g/mol
miu,C8H8=104g/mol
5kmol butadiena.........2kmol stiren..........1kmol copolimer
5x54kg.............................2x104kg.......................478kg
x..................................................y................................2390kg
x=m,teoretica=1350kg butadiena
y=m,teoretc=1040kg stiren
m,practca= m,teor/randament
m,pr=1687,5 kg butadiena
m,pr=1300kg stiren
Explicație:
