Răspuns:
c=mdx100/ms
c=5x100/400%= 1,25% fals
c,m= niu/V=13/2mol/l=6,5mol/l adevarat
o,2=niu/0,5---> niu=0,1mol Ca(OH)2
miu,Ca(OH)2=74g/mol=====> m=niuxmiu= 0,1x74g=7,4g Ca(OH)2 fals
miuMgO=40g/mol niu=m/miu-60/40mol=1,5mol
c,m-=niu.V----> V=1,5mol/5mol/l= 3=0,3 l=300ml adevarat
c3= md3x100./ms3, unde md3= md1+md2
ms3= ms1+ms2=300g
md1= c1xms1/100=0,3x150g=45g
md2= 0,15x150g=22,5g
md3= 67,5g
c3=67,5x100/300%=22,5% adevarat
Explicație:
