Cristinaconstanta9ask
a fost răspuns

x supra radical3 +radical12=radical27

Răspuns :

Targoviste44ask

[tex]\it \dfrac{x}{\sqrt3}+\sqrt{12}=\sqrt{27}\ \Rightarrow \dfrac{x}{\sqrt3}+\sqrt{4\cdot3}=\sqrt{9\cdot3}\ \Rightarrow\ \dfrac{x}{\sqrt3}+2\sqrt3=3\sqrt3|_{-2\sqrt3} \Rightarrow\\ \\ \\ \Rightarrow\ \dfrac{x}{\sqrt3}=\sqrt3 \Rightarrow x=\sqrt3\cdot\sqrt3\ \Rightarrow\ x=3[/tex]

Răspuns:

x/√3+√12=√27   ;amplific cu√3 ;   x+√36=√81 ;     x+6=9 ;   x=9-6 ;   x=3

Explicație pas cu pas:

Ask Alte intrebari