Răspuns :
a- dischete radu
b-dischete alin
a+b=135 (1)
a/3=b/2 => a= 3b/2... inlocuim in relatia (1) => 3b/2 + b =135.... amplificam a2-a fractie cu 2 =>(3b+2b)/2=135=> 5b=270=> b=270/5 => b=54... inlocuim iar in relatia (1) => a+54=135 => a = 135-54 = 81
b-dischete alin
a+b=135 (1)
a/3=b/2 => a= 3b/2... inlocuim in relatia (1) => 3b/2 + b =135.... amplificam a2-a fractie cu 2 =>(3b+2b)/2=135=> 5b=270=> b=270/5 => b=54... inlocuim iar in relatia (1) => a+54=135 => a = 135-54 = 81
Notam r=nr dischetelor lui Radu si a=nr dischete Alin
r/3=a/2=k
a=2k
r=3k
2k+3k=5k=135
k=135/5=27
Acum calculam nr de dischete al fiecaruia:
a=2k=2*27=54
r=3k=3*27=81
r/3=a/2=k
a=2k
r=3k
2k+3k=5k=135
k=135/5=27
Acum calculam nr de dischete al fiecaruia:
a=2k=2*27=54
r=3k=3*27=81