Răspuns:
[tex]( \frac{11}{6} + \frac{3}{4} ) \div \frac{31}{24} \\ (\frac{44}{24} + \frac{18}{24} ) \div \frac{31}{24} = \frac{62}{24 } \times \frac{24}{31} = \frac{62}{31} [/tex]
[tex]( \frac{5}{6} + \frac{11}{9} ) \div \frac{74}{9} \\ (\frac{ 15}{18} + \frac{22}{18} ) \div \frac{74}{9} = \frac{37}{18} \times \frac{9}{74} = \frac{37}{148} [/tex]
[tex]( \frac{1}{6} + \frac{17}{8} ) \div \frac{77}{24} + \frac{2}{7} \\ (\frac{4}{24} + \frac{51}{24} ) \div \frac{77}{24} + \frac{8}{24} = \frac{55}{24} \div \frac{85}{24} \\ \frac{55}{24} \times \frac{24}{85} = \frac{55}{85} = \frac{11}{17} [/tex]
[tex]( \frac{11}{12} - \frac{13}{18} ) \div 7 \\ (\frac{33}{36} - \frac{26}{36} ) \div 7 = \frac{7}{36} \div 7 \\ \frac{7}{36} \times \frac{1}{7} = \frac{1}{36} [/tex]
[tex]( \frac{19}{45 } - \frac{7}{30} ) \div \frac{34 }{5} \\ (\frac{38}{90} - \frac{21}{90}) \div \frac{34}{5} = \frac{17}{90} \div \frac{34}{5} \\ \frac{17}{90} \times \frac{5}{34} = \frac{1}{2} [/tex]
[tex]( \frac{13}{12} - \frac{7}{15} ) \div \frac{37}{30} + \frac{1}{2} \\ ( \frac{65}{60} - \frac{28}{60} ) \div \frac{37}{30} + \frac{15}{30} = \frac{40}{60} \div \frac{52}{30} \\ \frac{40}{60} \times \frac{30}{52} = \frac{80}{52} [/tex]
SPER CA T-IA FOST DE FOLOS
Explicație pas cu pas:
mai întâi aducem la acelasi ce este in paranteza dupa rezolvam paranteza si facem împărțirea care este o înmulțire doar ca trebuie scrisa cu numitorul la numărător si cu munaratorul la numitor
