Răspuns:
Explicație:
1,07 g Ag
Z Ag= 47 ------> 47e, 47p ,61n
AAg= 108
nr.e , nr.p , nr. n ?
-se afla nr. de moli de Ag din 1,07 g Ag
n= 1,07 g : 108g/moli= 0,0099 moli Ag
1mol Ag ------6,022.10²³atomi Ag-----47 . 6,022.10²³ p-----61 . 6,022. 10²³n
0,0099 moli Ag---------------------------------x------------------------------z
x= 0,0099 . 47 . 6,022.10²³p = 2,8041 .10²³ p
nr. p = nr e
y = 2,8041 .10²³e
z = 0,0099 . 61 .6,022.10²³n = 3,636.10²³n
