[tex] \frac{x}{2} = \frac{y}{3} = \frac{z}{4} = k[/tex]
[tex] \frac{x}{2} = k = > x = 2k[/tex]
[tex] \frac{y}{3} = k = > y = 3k[/tex]
[tex] \frac{z}{4} = k = > z = 4k[/tex]
2x + y + 5z=81 inlocuim cu k
[tex]2 \times 2k + 3k + 5 \times 4k = 81 \\ \\ 4k + 3k + 20k = 81 \\ 27k = 81 \\ k = 81 \div 27 \\ k = 3[/tex]
[tex]x = 2k \: si \: k = 3 = > x = 2 \times 3 = 6[/tex]
[tex]y = 3k \: si \: k = 3 = > y = 3 \times 3 = 9[/tex]
[tex]z = 4k \: si \: k = 3 = > z = 4 \times 3 = 12[/tex]
[tex] am \: folosit \: = > \\ \: pt \: semnul \: rezulta[/tex]
⛅️️️️️ʕ·ᴥ·ʔʔฅ^•ﻌ•^ฅ…ᘛ⁐̤ᕐᐷ⛅️⛅️
