[tex]\it F=\dfrac{a^2-b^2}{ab}\ \ \ \ \ \ \ (1)\\ \\ \\ a=\sqrt{12}\ \ \ \ \ \ (2)\\ \\ b=\sqrt3\ \ \ \ \ \ (3)\\ \\ \\ (2),\ (3) \Rightarrow a^2=(\sqrt{12})^2=12,\ \ b^2=(\sqrt3)^2=3,\ \ ab=\sqrt{12}\cdot\sqrt3=\sqrt{36}=6[/tex]
Raportul devine:
[tex]\it F= \dfrac{12-3}{6}=\dfrac{\ 9^{(3}}{6}=\dfrac{3}{2}=1,5[/tex]
