Răspuns :
Răspuns:
Sunt pe laptop deci nu pot face poza asa ca am sa iti explic
\ = supra * = ori(inmultire)
f) 3\5 + 8 - 26\5 - 29\10 * (1\5) la a doua = 311
3\5 + 8\1-26\5 - 29\10 * 1\10
3\5 + 8\1 - 26\5- 29\100 aici amplificam 3\5 cu 20, 8\1 cu 100 si 26\5 cu 20
60 + 800 - 520 -29
311
i) [(7\2)la a doua - (16\5)la a doua] *2 - 2 la a doua = 8
[14\4 - 32\10] *2 - 4 aici amplificam 14\4 cu 5 si 32\10 cu 2
[70\20 - 64\20] *2 - 4
6*2-4
12-4
8
F)3/5+8-26/5-29/10•(1/5)^2=
3/5+8-26/5-29/10•1/25=
3/5+8-26/5-29/250=821/250
i)((7/2)^2+(16/5)^2 )-2-2^2=
(49/4+(16/5)^2)-2-4=
49/4+(16/5)^-2-4=
49/4+256/25-2-4=
2249/100-6=1649/100
Coroana??
3/5+8-26/5-29/10•1/25=
3/5+8-26/5-29/250=821/250
i)((7/2)^2+(16/5)^2 )-2-2^2=
(49/4+(16/5)^2)-2-4=
49/4+(16/5)^-2-4=
49/4+256/25-2-4=
2249/100-6=1649/100
Coroana??