află necunoscută (e-5×6+10×5)-50+4×8=42​

Răspuns :

[tex](e - 5 \times 6 + 10 \times 5) - 50 + 4 \times 8 = 42[/tex]

[tex](e - 30 + 50) - 50 + 32 = 42[/tex]

[tex](e + 20) - 50 + 32 = 42[/tex]

[tex]e + 20 - 50 + 32 = 42[/tex]

[tex]e + 2 = 42[/tex]

[tex]e = 42 - 2[/tex]

[tex]e = 40[/tex]

Răspuns:

(e-30+50)-50+32=42

(e-30+50)-50=42-32

(e-30+50)-50=10

(e-30+50)=10+50

e-30+50=60

e-30=60-50

e-30=10

e=10+30

e=40