a.
nr.moli = V/Vm => V = nr.molixVm = 10x22,4 = 224 L
b.
nr.moli = V/Vm = N/NA.
=> N = VxN.A./Vm = 2,24x6,022x10la23/22,4 = 6,011x10la22 molecule
c.
PV = nRT
n.CO2 = m/M ; M = 12+2x16 = 44 g/mol
=> n.CO2 = 4/44 = 0,091 moli
=> P = nRT/V
= 0,091x0,082x(273+227)/2 = 1,86 atm
d.
PV = nRT; n= m/M ; p = m/V
=> PVM = mRT => PM = pRT/M ; M.NH3 = 14+3x1 = 17 g/mol
=> p = PM/RT = 2x17/0,082(273-3) = 1,54 g/L
