Răspuns:
date necesare:
miu,HCl=36,5g/mol
A,Mg=24g/mol
niu,HCl= m/miu=142/36,5mol=3,89molHCl
2mol........1mol.................1mol
2HCl + Mg-----> MgCl2 + H2
3,89mol........x....................y
x=1,945molMg
Y=1,945molH2
m,Mg=niuxA=1,945x24g=4,668g
Explicație: