Magda14ask
a fost răspuns

x+[tex]x+ \sqrt 2=0[/tex]

8 x = 0,16

[tex] x^{2} =6[/tex]

Răspuns :

Razvanw0wask
[tex]x+x+\sqrt2=0\\ 2x+\sqrt2=0\\ 2x=-\sqrt2\\ x=-\dfrac{\sqrt2}{2}\\ \\ 8x=0,16\\ x=\dfrac{0,16}{8}=0,02=\dfrac{1}{50}\\ \\ x^2=6 \Rightarrow x \in \lbrace \pm \sqrt6 \rbrace[/tex]

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