Explicație pas cu pas:
[tex] {x}^{2} = \frac{4}{9} = > x = \frac{ \sqrt{4} }{ \sqrt{9} } = \frac{2}{3} \\ {x}^{2} = \frac{18}{25} = \frac{ \sqrt{18} }{ \sqrt{25} } = > x = \frac{3 \sqrt{2} }{5} \\ [/tex]
[tex] {x}^{2} = \frac{16}{25} = > x = \frac{ \sqrt{16} }{ \sqrt{25} } = > x = \frac{4}{5} \\ {x}^{2} = \frac{8}{9} = > x = \frac{ \sqrt{8} }{ \sqrt{9} } = \frac{2 \sqrt{2} }{3} \\ {x}^{2} = 13 \frac{4}{9} = > x = \frac{ \sqrt{(13 \times 9) + 4} }{ \sqrt{9} } = \frac{ \sqrt{121} }{ \sqrt{9} } = \frac{11}{3} [/tex]
