2x+3y=5
x=(5-3y)/2
5x-3y=2
5×[(5-3y)/2]=2
(5-3y)/2=2/5
aducem tot la acelasi numitor si scapam de el (10)
25-15y = 4
15y=25-4=21
y=21/15=7/5=1,4
x=(5-3y)/2=(5-3×1,4)/2=(5-4,2)/2=0,8/2=(8/10)/2=8/5
