Salut,
[tex]\dfrac{4^{26}}{32^{11}}=\dfrac{(2^2)^{26}}{(2^5)^{11}}=\dfrac{2^{2\cdot 26}}{2^{5\cdot 11}}=\dfrac{2^{52}}{2^{55}}=2^{52-55}=2^{-3}}=\dfrac{1}{2^3}=\dfrac{1}8.[/tex]
Ai înțeles rezolvarea ?
Green eyes.
