[tex]\it a)\ \ \Big(\dfrac{3}{2}\Big)^{11}:\Big[\Big(\dfrac{3}{2}\Big)^2\Big]^4+\dfrac{3}{2}=\Big(\dfrac{3}{2}\Big)^{11}:\Big(\dfrac{3}{2}\Big)^8+\dfrac{3}{2}=\Big(\dfrac{3}{2}\Big)^3+\dfrac{3}{2}=\dfrac{27}{8}+\dfrac{^{4)}3}{\ 2}=\\ \\ \\ =\dfrac{27+12}{8}=\dfrac{39}{8}=4\dfrac{7}{8}[/tex]
