[tex]\it AB<AC<BC\\ \\ DF<DE<EF\\ \\ \left.\begin{aligned}\it \dfrac{AB}{DF}=\dfrac{^{4)}3}{\ 2,25}=\dfrac{\ 12^{(3}}{9}=\dfrac{4}{3}\\ \\ \\ \it \dfrac{AC}{DE}=\dfrac{4}{3}.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ .\\ \\ \\ \it\dfrac{BC}{EF}=\dfrac{^{4)}5}{\ 3,75}=\dfrac{\ 20^{(5}}{15}=\dfrac{4}{3}\end{aligned}\right\}\ \Rightarrow \dfrac{AB}{DF}=\dfrac{AC}{DE}=\dfrac{BC}{EF}[/tex]
