1)m(A)+m(B)+m(C)=180, 90+60+m(C)=180=>m(C)=30
sinB=[tex] \frac{AC}{BC} =>BC= \frac{AC}{sinB}= \frac{8 \sqrt{3} }{ \frac{ \sqrt{3} }{2} }=16 [/tex]
cosB=[tex] \frac{AB}{BC}=>AB=BC*cosB=16* \frac{1}{2}=8 [/tex]
2)[tex]sinC= \frac{1}{2}=>m(C)=30 [/tex]
m(A)+m(B)+m(C)=180,
90+30+m(B)=180=>m(B)=60
cosC=[tex] \frac{AC}{BC}=>BC= \frac{AC}{cosC} = \frac{3}{ \frac{ \sqrt{3} }{2} } =2 \sqrt{3}[/tex]
tgC=[tex] \frac{AB}{AC}=>AB=AC*tgC=3* \frac{ \sqrt{3} }{3} = \sqrt{3} [/tex]