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Rezolvati inecuatiile:
1) 5(x+2)+4(x+2)<3(x+8)+12
2)4(x+5)+3(x+3)<2(x+15)+4
DAU COROANA!!!
VA ROG REPEDE!​

Răspuns :

Pateugucciask

1.

[tex]5(x + 2) + 4(x + 2) < 3(x + 8) + 12 \\ 5x + 10 + 4x + 8 < 3x + 24 + 12 \\ 9x + 18 < 3x + 36 \\ 6x < 18 \\ x < 3[/tex]

=> x apartine (-infinit; 3)

2.

4(x+5)+3(x+3)<2(x+15)+4

4x+20+3x+9<2x+30+4

7x+29<2x+34

5x<5

x<1

=>x apartine (-infinit; 1)

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