Răspuns:
3.3
v= 0,04m³=40 l
m=0,14kg=140g
miuN2=28g/mol
niu=m/miu=140/28mol=5mol
T=273+27=>300K
pxV=niuRT
px40=5x0,082x300-------> p=3atm
niu=niuN2+niuCO2
p=3,69
3,69x40=niux0,082x300----> nIu=6mol
niu,CO2=6-5=> 1mol
niu,total =6mol
V=niuxVm=6x22,4 l=134,4 l
4.4
m=335g
V=41 L
T=273+100=373K
p=3,73atm
niu=m/miu
pV=niuRT
pV=mRT/miu
3,73x41=355x0,082x373/miu=====> miu=71g/mol----> CL2
Explicație:
