Răspuns:
#include<iostream>
using namespace std;
int n,a[202][202],i,j;
float media,media2,kontor,kontor2,suma,suma2;
int main()
{
cin>>n;
for(i=1;i<=n;i++)
for(j=1;j<=n;j++)
cin>>a[i][j];
for(i=1;i<=n;i++)
for(j=1;j<=n;j++)
if(i<j && a[i][j]>=0)
{
kontor++;
suma+=a[i][j];
}
else if(i>j && a[i][j]>=0)
{
kontor2++;
suma2+=a[i][j];
}
media=suma/kontor;
media2=suma2/kontor2;
cout<<double(media-media2);
}
Explicație: