Răspuns:
a.
p=m,px100/m,i---> m,p= 85x50/100g=42,5g Mgpur
.
A,Mg=24g/mol
miu,HCl=36,5g/mol ; miuMgCl2=95g/mol
Vm=22,4 l/mol
24g......2x36,5g......95g...........22,4 l
Mg + 2HCl---> MgCl2 + H2
42,5..........x.................y..............z
b. x=m=129,3gHCl=md
c=mdx100/ms---> ms= 129,3x100/20g=646,5g sol
c. z=V=39,7 l H2
d. y=m=168,2 gMgCl2=md
m,apa= msHCl-md,HCl=646,5-129,3>=517,2g
ms,sare=md,sare+m.apa=168,2+517,2=>685,4g
c= md,sarex100/m,s= 168,2x100/685,4=24,5%
Explicație:
