Răspuns:
2n+1 | 6 => (2n+1) € div 6={ 1, 2, 3, 6} => 2n+1= 1 <=> 2n=0 => n1= 0
2n+1= 2 <=> 2n= 1 => n2= 1/2 => n2 nu e posibil
2n+1= 3 <=> 2n= 2 => n3= 1
2n+1= 6 <=> 2n= 5 => n4= 5/4 => n4 nu e posibil
=> n={0, 1}
Coroniță?
