Răspuns:
Explicație pas cu pas:
d) (2^40(1+2))/3^25 =
3*2^40/(3*3^24) =
2^40/3^24 = 4^20/9^12 =
16^10/9^12 = 256^5/81^6 =
256^5/(81*81^5) =
1/81 * (256/81)^5
256/81 = 3,16 , luam 3
3^5/81 = 3*81/81 = 3 > 1
h) 3^22(3^2+3 -1)/(9^11(1+9)) =
9^11*11/(9^11*10) =
11/10 > 1
