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Răspuns: Varianta B) n ∈ IN
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[tex]\bf \dfrac{n+1}{3n+4} \longrightarrow fractie~ireductibila[/tex]
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[tex]\bf \underline{n=0} \implies \dfrac{0+1}{3\cdot 0+4} = \dfrac{1}{4} \longrightarrow fractie~ireductibila[/tex]
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[tex]\bf \underline{n=1} \implies \dfrac{1+1}{3\cdot 1+4} = \dfrac{1}{7} \longrightarrow fractie~ireductibila[/tex]
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[tex]\bf \underline{n=2} \implies \dfrac{2+1}{3\cdot 2+4} = \dfrac{3}{10} \longrightarrow fractie~ireductibila[/tex]
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[tex]\bf \underline{n=3} \implies \dfrac{3+1}{3\cdot 3+4} = \dfrac{4}{13} \longrightarrow fractie~ireductibila[/tex]
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[tex]\bf \underline{n=4} \implies \dfrac{4+1}{3\cdot 4+4} = \dfrac{5}{16} \longrightarrow fractie~ireductibila[/tex]
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[tex]\bf \underline{n=5} \implies \dfrac{5+1}{3\cdot 5+4} = \dfrac{6}{19} \longrightarrow fractie~ireductibila[/tex]
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[tex]\text{\bf Observam ca fractia e ireductibila pentru}~\bf \underline{n\in \mathbb{N}}[/tex]
Varianta B) n ∈ IN
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