7878÷39-2×10⁰+(6+2³×2⁷÷2⁸)²


Răspuns :

Salut!

7878÷39-2×10⁰+(6+2³×2÷2⁸)² =

7878÷39-2×10⁰+(6+2³÷2⁸)² =

7878÷39-2×10⁰+(6+2¹÷2)² =

7878÷39-2×10⁰+(6+2¹)² =

7878÷39-2×10⁰+(6+2²)² =

7878÷39-2×10⁰+(6+2²ˣ²) =

7878÷39-2×10⁰+(6+2) =

7878÷39-2×10⁰+(6+16) =

7878÷39-2×10+22 =

7878÷39-2×1+22 =

202-2×1+22 =

202-2+22 =

200+22

222

Formule folosite:

aᵐ × aⁿ = aᵐ⁺ⁿ ( a ≠ 0 )

aᵐ ÷ aⁿ = aᵐ⁻ⁿ ( a ≠ 0 )

( aᵐ )ⁿ = aᵐ ˣ ⁿ ( a ≠ 0 )

Răspuns:

300

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