media geometrica a=16 radical 3 si b=12 radical 3 este..
rapid va rog dau coroana


Răspuns :

[tex]m = \sqrt{a \times b} = \sqrt{16 \sqrt{3} \times 12 \sqrt{3} } = \sqrt{16 \times 12 \times 3} = \sqrt{576} = 24[/tex]

Răspuns: [tex]\bf Mg =24[/tex]

Explicație pas cu pas:

Salutare!

[tex]\color{magenta}\boxed{\boxed{\bf Media~geometrica = \sqrt{a\cdot b}~~unde~a,b\geq 0}}[/tex]

[tex]\bf a = 16\sqrt{3}[/tex]

[tex]\bf b= 12\sqrt{3}[/tex]

[tex]\bf Mg = \sqrt{16\sqrt{3} \cdot 12\sqrt{3}}[/tex]

[tex]\bf Mg = \sqrt{16\cdot3 \cdot 12}[/tex]

[tex]\bf Mg = \sqrt{576}[/tex]

[tex]\bf Mg = \sqrt{24^{2}}[/tex]

[tex]\boxed{\boxed{\bf Mg =24}}[/tex]

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