Răspuns:
Explicație pas cu pas:
[tex]\frac{9^{15} }{27^{10} }} = \frac{(3^{2}) ^{15} }{(3^{3}) ^{10} }} = \frac{3^{30} }{3^{30} } = (\frac{3}{3})^{30}[/tex] echiunitara
[tex]\frac{19^{7}}{2^{28}} = \frac{19^{7}}{(2^{4}) ^{7}} = \frac{19^{7}}{16 ^{7}} = (\frac{19}{16})^{2}[/tex] supraunitara
[tex]\frac{5^{30} }{3^{45} } = \frac{(5^{2})^{15} }{(3^{3}) ^{15} } = \frac{25^{15} }{27^{15} } = (\frac{25}{27} )^{15}[/tex] subunitara
