Răspuns:
Explicație:
2moli Ca(OH)2
react. cu HCl
ec.
g,moli HCl
Vs HCl
cm=2moli/L
xmoli 2moli
2HCl + Ca(OH)2 = CaCl2 + 2H2O
2moli 1mol
x= 2 . 2 : 1= 4moli HCl
m= n . M
MHCl= 1+ 35,5=36,5-----> 36,5g/moli
m= 4moli. 36,5g/moli=146g HCl
cm= n : Vs cm----->concentratie molara
Vs= n : cm
Vs= 4moli : 2moli/L= 2 L HCl