Răspuns:
a/3=b/5=c/7=k
=> a=3k
b=5k
c=7k
a²+b²+c²=332
(3k)²+(5k)²+(7k)²=332
9k²+25k²+49k²=332
83k²=332 => k²=4
a, b, c ∈ N
=> k=2
deci, a=3k=3×2=6
b=5k=5×2=10
c=7k=7×2=14
