Răspuns:
Explicație pas cu pas:
a) in Δ dreptunghic VOA VA=6 cm AO=AC/2=6√2/2=3√2 cm
VO²=VA²-AO²=36-18=18 ⇒V0=3√2 cm
calculam VM apotema M∈BC VO⊥(ABCD) VO⊥BC
⇒cf teoremei celor 3 perpendiculare VM⊥BC
in ΔVOM VM²=VO²+OM²
OM=AB/2=6/2=3 cm VM²=18+9=27 ⇒VM=3√3cm
a)Al=4×Avbc=4×VM×BC/2=2×3√3×6=36√3 cm²
b) translatam AD in BC
unghiul (AD, BP)=∡(BC, BP) ???? VP>VC