Răspuns:
[tex] {x}^{2} - 2 \times x \times 2 + {2}^{2} - x + 2 = {x}^{2} - 2x - x + 2(x - 3) \\ {x}^{2} - 4x + 4 - x + 2 = {x}^{2} - 2x - x + 2x - 6 \\ {x}^{2} - 5x + 6 = {x}^{2} - x - 6 \\ {x}^{2} - {x}^{2} - 5x + x + 6 + 6 = 0 \\ - 4x + 12 = 0 \\ - 4x = 12 \\ x = - \frac{4}{12} \\ x = - \frac{1}{3} [/tex]
sper sa fie corect, coroana
