Răspuns :
Răspuns:
a) MCO2=12+2×16=44g/mol
MNaOH=23+16+1=40g/mol
MAl(OH)3=27+3×16+3×1=78g/mol
MAl2O3=2×27+3×16=102g/mol
MFe(OH)3=56+3×16+3×1=107g/mol
b)
1mol CO2=44g
1molNaOH=40g
1mol Al(OH)3=78g
1mol Al2O3=102
1mol Fe(OH)3=107g
Explicație:
Răspuns:
a) MCO2=12+2×16=44g/mol
MNaOH=23+16+1=40g/mol
MAl(OH)3=27+3×16+3×1=78g/mol
MAl2O3=2×27+3×16=102g/mol
MFe(OH)3=56+3×16+3×1=107g/mol
b)
1mol CO2=44g
1molNaOH=40g
1mol Al(OH)3=78g
1mol Al2O3=102
1mol Fe(OH)3=107g
Explicație: