Explicație pas cu pas:
[tex]( \sqrt{3} - \sqrt{2} )^{2} = \\ ( \sqrt{3} ) ^{2} - 2 \times \sqrt{3} \times \sqrt{2} + ( \sqrt{2} )^{2} = \\ 3 - 2 \sqrt{6} + 2 = 5 - 2 \sqrt{6} [/tex]
Răspuns:
[tex]5-2\sqrt{6}[/tex]
[tex](\sqrt{3}-\sqrt{2})^{2}=(\sqrt{3})^{2} -2*\sqrt{3} * \sqrt{2} +(\sqrt{2})^{2}=3-2*\sqrt{3}*\sqrt{2} +2=5-2 \sqrt{6}[/tex]
