(x-3)(y+4)=12
=> I. x-3=6 => x=9
y+4=2 => y=-2
dar y∈ℕ => y∈Ø
II. x-3=2 => x=5
y+4=6 => y=2
III. x-3=3 => x=6
y+4=4 => y=0
IV. x-3=4 => x=7
y+4=3 => y=-1
dar y∈ℕ => y∈Ø
V. x-3=12 => x=15
y+4=1 => y=-3
dar y∈ℕ => y∈Ø
VI. x-3=1 => x=4
y+4=12 => y=8
(x, y) ={(5,2);(6,0);(4,8)}
Kawaiimath
