[tex]\displaystyle\bf\\a)~(x-1)^2=16,~extragem~radacina~patrata~din~ambii~membri \implies\\\sqrt{(x-1)^2} = \sqrt{16}~\Leftrightarrow |x-1|=4 \Leftrightarrow x-1=\pm 4.\\1.~x-1=4\implies x=5.\\2.~x-1=-4\implies x=-3.\\\\b)~(x-3)^2=36,~extragem~radacina~patrata~din~ambii~membri \implies\\\sqrt{(x-3)^2} = \sqrt{36} \Leftrightarrow | x-3| = 6 \Leftrightarrow x-3=\pm 6.\\1.~x-3=6 \implies x=9.\\2.~x-3=-6 \implies x=-3.\\[/tex][tex]\displaystyle\bf\\\\c)~(x+5)^2=49,~extragem~radacina~patrata~din~ambii~membri \implies \sqrt{(x+5)^2} = \sqrt{49} \Leftrightarrow |x+5|=7 \Leftrightarrow x+5=\pm 7.\\1.~x+5=7 \implies x = 2.\\2.~x+5=-7 \implies x = -12.\\\\d)~(x+2)^2=25,~extragem~radacina~patrata~din~ambii~membri \implies\\\sqrt{(x+2)^2} = \sqrt{25} \Leftrightarrow |x+2|=5 \Leftrightarrow x+2=\pm 5.\\1.~x+2=5 \implies x=3.\\2.~x+2=-5 \implies x=-7.[/tex]
