-1 +6 0 +2
KI + H2SO4 --> K2SO4 + I2 + H2S + H2O
2x 2I⁻ _+2e-_> I⁰2 oxidare (ag. reducator, KI)
1x S⁶⁺_+4e-_> S²⁺ reducere (ag. oxidant, H2SO4)
M.KI = 39+127 = 166 g/mol
266g n moli
8KI + 5H2SO4 --> 4K2SO4 + 4I2 + H2S + 4H2O
8x166 5
=> n = 266x5/8x166 = 1 mol H2SO4
stim ca Cm = n/Vs
=> Vs = n/Cm = 1/6 = 0,166 L sol. H2SO4
