[tex]a) \: 6 \times 14 - 2 \times (40 - 27 \div 3)[/tex]
[tex]b) \: 1012 - 5 \times (9 \div 3 \times 3 + 202 \div 2)[/tex]
[tex]c) \: (6 \times 14 - 2) \times (40 - 27 \div 3)[/tex]
[tex]d) \: [(2 \times {3}^{2} + 3 \times {2}^{2}) \: \div 6 + {5}^{2}] \div 5 + {10}^{2} [/tex]
ꨄ︎ ꨄ︎


✞︎48 ✞︎​


Răspuns :

Mult succes :))))

Plss coroana :))))

Vezi imaginea Flamandemanuel

Răspuns: Ai rezolvarea mai jos pentru fiecare subpunct

Explicație pas cu pas:

Salutare!

[tex]\bf \:a) \: 6\cdot 14 - 2\cdot (40-27:3)=[/tex]

[tex]\bf 84 - 2\cdot (40-9)=[/tex]

[tex]\bf 84 - 2\cdot 31=[/tex]

[tex]\bf 84 - 62 =[/tex]

[tex]\boxed{\bf 22}[/tex]

[tex]\bf \:b) \: 1012 -5\cdot(9:3\cdot 3 +202:2)=[/tex]

[tex]\bf 1012 -5\cdot(3\cdot 3 +101)=[/tex]

[tex]\bf 1012 -5\cdot(9 +101)=[/tex]

[tex]\bf 1012 -5\cdot 110=[/tex]

[tex]\bf 1012 -550 =[/tex]

[tex]\boxed{\bf 462}[/tex]

[tex]\bf \:c) \: (6\cdot 14 -2)\cdot(40 -27:3)=[/tex]

[tex]\bf (84 -2)\cdot(40 -9)=[/tex]

[tex]\bf 82\cdot 31=[/tex]

[tex]\boxed{\bf 2542}[/tex]

[tex]\bf \:d) \: [(2\cdot 3^{2} +3\cdot 2^{2}):6+5^{2}]:5+10^{2}=[/tex]

[tex]\bf [(2\cdot 9 +3\cdot 4):6+25]:5+100=[/tex]

[tex]\bf [(18 +12):6+25]:5+100=[/tex]

[tex]\bf (30:6+25):5+100=[/tex]

[tex]\bf (5+25):5+100=[/tex]

[tex]\bf 30:5+100=[/tex]

[tex]\bf 6+100=[/tex]

[tex]\boxed{\bf 106}[/tex]

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