1.
n natural
citeste n
cat timp n>4 si n<1000 executa citeste n
2.
n, s naturale
s <- 0
citeste n
cat timp n>=1 executa
{
s <- s+n
citeste n
}
scrie s
C++
1.
#include <iostream>
using namespace std;
int main()
{
int n;
cin >> n;
while (n>4 && n<1000) cin >> n;
return 0;
}
2.
#include <iostream>
using namespace std;
int main()
{
int n, s=0;
cin >> n;
while (n>=1)
{
s=s+n;
cin >> n;
}
cout << s;
return 0;
}
