Răspuns:
Faceti un desen conf. problemei.
Se vede ca EAvector+ADvector=ED vector Cum ANvector=kADvactor=k(EDvector-EAvector) si la fel ;EBvector+BCvector=ECvector Cum BMvector=k.BCvector=k(ECvector-
-EBvector )=k(ECvector+EA vector). Deci;EMvector=EBvector+BMvctor=k.ECvector+(k-1)EAvector
(EAvector=-EBvector)
si ENvector=EAvector+ANvector=kEDvector+(1-k)EAvector
am folosit k in loc de alfa