Răspuns:
Explicație pas cu pas:
[tex](\frac{5}{\sqrt28} } -\frac{2\sqrt{7} }{7} +\frac{3}{2\sqrt{7} } ):\frac{1}{\sqrt{14} } =\\ \\ =(\frac{5}{2\sqrt{7} } } -\frac{2\sqrt{7} }{7} +\frac{3}{2\sqrt{7} } ):\frac{1}{\sqrt{14} } =\\ \\ =(\frac{1}{\sqrt{7} } -\frac{2\sqrt{7} }{7} )\cdot\sqrt{14} =\\ \\ =(\frac{\sqrt{7} }{7} -\frac{2\sqrt{7} }{7} )\cdot\sqrt{14} =\\ \\ =\frac{\sqrt{7} }{7} \cdot\sqrt{7} \cdot\sqrt{2} =\\ \\ =\sqrt{2}[/tex]
