Răspuns:
a)5
b) 4.1
Explicație pas cu pas:
a) [tex]\left(16.5-\frac{13\cdot9+7}{9}\right)\cdot\frac{6}{11}+2.2\left(\frac{8}{33}-\frac{1}{11}\right)+\frac{3\cdot11+2}{11}[/tex]
[tex]=\left(\frac{33}{2}-\frac{124}{9}\right)\cdot\frac{6}{11}+\frac{11}{5}\cdot\frac{5}{33}+\frac{35}{11}[/tex]
[tex]=\frac{49}{18}\cdot\frac{6}{11}+\frac{1}{3}+\frac{35}{11}[/tex]
[tex]=\frac{49}{3}\cdot\frac{1}{11}+\frac{1}{3}+\frac{35}{11}\\[/tex]
[tex]=\frac{49}{33}\cdot\frac{1}{11}+\frac{1}{3}+\frac{35}{11}=5[/tex]
b)[tex]\frac{\left(1\frac{1}{7}-\frac{23}{49}\right)}{\frac{22}{147}}-\left(0.6+3\frac{3}{4}\right)\cdot2\frac{1}{2}=[/tex]
[tex]=\left(\frac{8}{7}-\frac{23}{49}\right)\cdot\frac{147}{22}-\left(\frac{\frac{3}{5}}{\frac{15}{4}}\right)\cdot\frac{5}{2}\\[/tex]
[tex]=\frac{33}{49}\cdot\frac{147}{22}-\left(\frac{3}{5}\cdot\frac{4}{15}\right)\cdot\frac{5}{2}[/tex]
[tex]=3\cdot\frac{3}{2}-\left(\frac{1}{5}\cdot\frac{4}{5}\right)\cdot\frac{5}{2}[/tex]
[tex]=\frac{9}{2}-\frac{4}{25}\cdot\frac{5}{2}[/tex]
[tex]=\frac{9}{2}-\frac{2}{5}[/tex]
[tex]=\frac{41}{10}=4.1[/tex]
